How do you write the equation for a circle with center (-2,-3) and r = 3?

2 Answers

Answer:

#(x+2)^2+(y+3)^2=9#

Explanation:

The equation of a circle is:

#(x-h)^2+(y-k)^2=r^2# where h and k are the x and y values of the centre and r is the radius. We can plug in the given values to find the equation of this circle:

#(x+2)^2+(y+3)^2=3^2=9#

May 28, 2016

Answer:

#(x+2)^2+(y+3)^2=9#

Explanation:

The standard form of the equation of a circle is.

#color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))#
where (a ,b) are the coordinates of the centre and r, the radius.

here a = -2 , b = -3 and r = 3

Substitute these values into the standard equation.

#rArr(x+2)^2+(y+3)^2=9" is the circle's equation."#