# How do you write the equation for a circle with Center of circle (8,4) radius with endpoint (0,4)?

##### 1 Answer

May 1, 2016

#### Answer:

The answer is:

#### Explanation:

You can find the reason for this based on the standard equation of a circle, which is:

Using the standard form, we can deconstruct the given information as such:

#(h, k)# of the circle is#(8, 4)# , since#(8, 4)# represents the center of the circle.- The radius of the circle is 8. We know this because a circle is defined as the set of all point equidistant from the center of the circle, and, if one of the endpoints is at
#(0, 4)# , then the distance between it and the center#(8, 4)# is 8 (there's no change in y-values). Thus, we can plug each of the values into the standard equation:

*Note that you would have had to use the distance formula if the y-coordinate was not the same.

Graphically:

graph{(x-8)^2+(y-4)^2=64 [-8.78, 27.27, -5.02, 13]}