How do you write the equation for a circle with Origin: (5,5) ; Radius = 2?

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Answer 1 · 2016-06-11T16:37:30

#x^2+y^2-10x-10y+46=0#.

The equation of the circle is

#(x-c_x)^2+(y-c_y)^2=r^2#.

Where #c_x# and #c_y# are the coordinates of the center and #r# is the radius.

Then we have

#(x-5)^2+(y-5)^2=2^2#

#x^2-10x+25+y^2-10y+25=4#

#x^2+y^2-10x-10y+50=4#

#x^2+y^2-10x-10y+46=0#.