# How do you write the equation in point slope form given (-1, -2), perpendicular to y = -3x + 3?

$y - - 2 = \frac{1}{3} \left(x - - 1\right) \text{ " }$point slope form

#### Explanation:

We have a given point $\left({x}_{1} , {y}_{1}\right) = \left(- 1 , - 2\right)$ and the line is suppose to contain this point with a slope $m = - \frac{1}{- 3} = \frac{1}{3}$

point slope form: $\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

$y - - 2 = \frac{1}{3} \left(x - - 1\right)$

the graph of the lines look like as follows

graph{(y--2-1/3(x--1))(y+3x-3)=0[-10,10,-5,5]}

God bless...I hope the explanation is useful...