# How do you write the equation in point slope form given (-3,1) and has a slope of -2?

Feb 26, 2016

$y - 1 = - 2 \left(x + 3\right)$

#### Explanation:

To determine the equation of the line we can use the point slope formula and plug in the values (-3 , 1) and slope of -2 given in the question.

$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

$m = - 2$
${x}_{1} = - 3$
${y}_{1} = 1$

$\left(y - 1\right) = - 2 \left(x - \left(- 3\right)\right)$

The point-slope form is the following:

$y - 1 = - 2 \left(x + 3\right)$

Solve for $y$ to get the slope-intercept form (this isn't necessary since the question asked for point-slope form).

$y - 1 = - 2 x - 6$

$y - 1 + 1 = - 2 x - 6 + 1$

$y = - 2 x - 5$

Slope-intercept form is $y = m x + b$, where $m$ is the slope and $b$ is the y-intercept.