How do you write the equation in slope intercept form perpendicular to y = -4x -2 and passes through the point (-16, -11)?

1 Answer
Mar 5, 2016

$y ' = \frac{1}{4} x ' - 7$

Explanation:

$y = - 4 x - 2$

$\implies m = - 4$

$m ' = - \frac{1}{m}$

$\implies m ' = - \frac{1}{-} 4 = \frac{1}{4}$

$y ' = m ' x ' + b '$

$\implies y ' = \frac{1}{4} x ' + b '$

$\implies - 11 = \frac{1}{4} \left(- 16\right) + b '$

$\implies - 11 = - 4 + b '$

$\implies b ' = - 7$

$y ' = \frac{1}{4} x ' - 7$