How do you write the equation in standard form 5y-1/3x=-8?

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How do you write the equation in standard form 5y-1/3x=-8?

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Answer 1 · 2018-04-19T07:30:10

$y = \frac{24 x + 1}{5}$ $y=(24x+1)/5$

Explanation:

$\frac{5 y - 1}{3 x} = 8$ $(5y-1)/(3x)=8$
$(5 y - 1) = 8 (3 x)$ $(5y-1)=8(3x)$
$5 y - 1 = 24 x$ $5y-1=24x$
$5 y = 24 x + 1$ $5y=24x+1$
$y = \frac{24 x + 1}{5}$ $y=(24x+1)/5$

The standard form for a linear equation is in the form $y = x + b$ $y=x+b$ , therefore, we want to isolate y. To do this, first, we want to get rid of the denominator, which is done by multiplying both sides of the equation by $3 x$ $3x$ . The denominator would cancel out on the left side. Then add $1$ $1$ to both sides of the equation to remove it from the left side. After isolating $5 y$ $5y$ , $y$ $y$ can be isolated by dividing both sides by $5$ $5$ . This gives the answer, $y = \frac{24 x + 1}{5}$ $y=(24x+1)/5$ .

Answer 2 · 2018-04-19T07:37:13

$x - 15 y = 24$ $x-15y=24$

Explanation:

$the equation of a line in standard form$ $"the equation of a line in "color(blue)"standard form"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))$

$"where A is a positive integer and B, C are integers"$

$"multiply all terms by "-3$

$rArr-15y+x=24$

$rArrx-15y=24larrcolor(red)"in standard form"$

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How do you write the equation in standard form 5y-1/3x=-8?

2 Answers

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