# How do you write the equation in standard form 5y-1/3x=-8?

Apr 19, 2018

$y = \frac{24 x + 1}{5}$

#### Explanation:

$\frac{5 y - 1}{3 x} = 8$
$\left(5 y - 1\right) = 8 \left(3 x\right)$
$5 y - 1 = 24 x$
$5 y = 24 x + 1$
$y = \frac{24 x + 1}{5}$

The standard form for a linear equation is in the form $y = x + b$, therefore, we want to isolate y. To do this, first, we want to get rid of the denominator, which is done by multiplying both sides of the equation by $3 x$. The denominator would cancel out on the left side. Then add $1$ to both sides of the equation to remove it from the left side. After isolating $5 y$, $y$ can be isolated by dividing both sides by $5$. This gives the answer, $y = \frac{24 x + 1}{5}$.

Apr 19, 2018

$x - 15 y = 24$

#### Explanation:

$\text{the equation of a line in "color(blue)"standard form}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{A x + B y = C} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\text{where A is a positive integer and B, C are integers}$

$\text{multiply all terms by } - 3$

$\Rightarrow - 15 y + x = 24$

$\Rightarrow x - 15 y = 24 \leftarrow \textcolor{red}{\text{in standard form}}$