# How do you write the equation in standard form #x^2 + y^2 - 4x - 14y + 29 = 0#?

##### 1 Answer

Dec 1, 2015

Complete the square for

#(x-2)^2+(y-7)^2 = 24#

or if you prefer:

#(x-2)^2+(y-7)^2 = (sqrt(24))^2#

which is in standard

#### Explanation:

#0 = x^2+y^2-4x-14y+29#

#=(x^2-4x+4)+(y^2-14y+49)+(29-4-49)#

#=(x-2)^2+(y-7)^2-24#

Add

#(x-2)^2+(y-7)^2 = 24#

This is the equation of a circle with centre