# How do you write the equation of a circle with a center at (6, 7) and a diameter of 4?

${\left(x - 6\right)}^{2} + {\left(y - 7\right)}^{2} = {2}^{2}$
${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$ is the general equation where $\left(h , k\right)$ is the center. $r$ is radius thus it equals to $\frac{1}{2}$ of diameter, $r$= 2.