Question

How do you write the equation of a circle with a center at (6, 7) and a diameter of 4?

Answer 1

`(x-6)^2 + (y-7)^2 = 2^2`

Explanation:

`(x-h)^2 + (y-k)^2 = r^2` is the general equation where `(h,k)` is the center. `r` is radius thus it equals to `1/2` of diameter, `r`= 2.