How do you write the equation of a line in point slope form and slope intercept form given points (-3, -4) (3, -2)?

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Answer 1 · 2015-05-07T20:07:40

Since both requested forms require the slope, let's start there:

$m= (Delta y)/(Delta x)$

$= ((-2)-(-4))/(3-(-3))$

$=2/6 = 1/3$

The general point slope form is
$(y-y-1) = m(x-x_1)$
or, in our example,
$y-(-4) = 1/3(x-(-3))$

With a little rearranging we can convert this into the slope intercept form (which in general is $y=mx+b$ with a y-intercept at $b$ )

$y+4 = 1/3(x+3)$

$y+4 = 1/3x +1$

$y= 1/3x -3$