How do you write the equation of a line in point slope form that is parallel to #y=7x-1# and goes through (1,-2)?

1 Answer
May 7, 2015

Point-slope form of an equation for a line is
#(y-y_1) = m(x-x_1)#
for a line with slope #m# through a point #(x_1,y_1)#

Slope (y)intercept form for a line is
#y=mx+b#
for a line with slope #m# and a y-intercept of #b#

The given line #y=7x-1# is in slope-intercept form with a slope of #m=7#

Any line parallel to this will also have a slope of #m=7#

Point-slope form of an equation for a line with #m=7# through the point #(1,-2)# is
#(y-(-2)) = 7(x-1)#
which you might simplify as
#y+2 = 7(x-1)# (although this "hides" the true #y# coordinate value)