# How do you write the equation of the circle whose diameter has endpoints (-1,0) and (6,-5)?

##### 1 Answer

Sep 16, 2016

#### Answer:

#### Explanation:

If

then, its eqn. is given by,

Applying this, we can immediately get the eqn. of circle as,

**Alternatively,**

Knowing that the mid-pt. of a diameter is the Centre of the Circle,

we get the Centre

Now, the pt.

the Centre, the dist.

Hence, the eqn of the circle is

#(x-5/2)^2+(y+5/2)^2=74/4, or,

#x^2+y^2-5x+5y+25/4+25/4-74/4=0, i.e.,

Enjoy Maths.!