# How do you write the equation of the circle with center (4, 0) and r=sqrt5?

Jun 17, 2016

${\left(x - 4\right)}^{2} + {y}^{2} = 5$

#### Explanation:

center(4,0)
r=$\sqrt{5}$
circle can be thought as a set which every points to the center are same distance
use distance formula to describe
$\sqrt{{\left(x - 4\right)}^{2} + {\left(y - 0\right)}^{2}} = \sqrt{5}$
$\to {\left(x - 4\right)}^{2} + {y}^{2} = 5$