Question

How do you write the equation of the circle with diameter endpoints of (5,8) and (5,-4)?

Answer 1

`(x-5)^2+(y-2)^2=36`

Explanation:

If the diameter endpoints of a circle are at `(5,8)` and `(5,-4)`
the center of the circle is at `(5,2)`
and its radius is `6`

graph{(x-5)^2+(y-2)^2=36 [-11.28, 17.19, -5.52, 8.72]}