# How do you write the equation of the line in the form AX+BY=C if m= 1/2, P (6,1)?

$y = m x + b \implies y = \frac{1}{2} x + b$ Hence point P(6,1) is on the line we have that
$1 = \frac{1}{2} \cdot 6 + b \implies 1 = 3 + b \implies b = - 2$ so the equation is $y = \frac{1}{2} x - 3$ or
$2 y = x - 3 \implies \left(- 1\right) \cdot x + 2 \cdot \left(y\right) = - 3$ hence A=-1 , B=2 ,C=3