# How do you write the equation of the line through (-2, -1) that is parallel to the line 5x + 3y =9?

$y = \frac{- 13 - 5 x}{3}$
Get y by itself for an easier graph equation, $3 y = 9 - 5 x$, $y = \frac{9 - 5 x}{3}$. Plugging in $- 2$ gets you $6 \frac{1}{3}$. In order to get a parallel equation to run through $\left(- 2 , - 1\right)$, you need to shift the y down by $7 \frac{1}{3}$. So $y = \frac{9 - 5 x}{3} - 7 \frac{1}{3}$. Which can be simplified to $y = \frac{- 13 - 5 x}{3}$.