Question

How do you write the equation of the line with the slope of a line is 1/8 and the point (-8, -5) is on the line?

Answer 1

You can use the general relationship:
`y-y_0=m(x-x_0)`
with `m=1/8` which is the slope;
`x_0=-8` and `y_0=-5`
Giving:
`y+5=1/8(x+8)`
and finally:
`y=1/8x-4`