How do you write the equation #x^2+y^2=-3x# into polar form?

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Answer 1 · 2017-01-26T16:12:43

#r=-3costheta#

the conversion from Cartesian to polars

#r^2=x^2+y^2#

#x=rcostheta#

#y=rsintheta#

so we substitute into the eqn

#x^2+y^2=-3x#

#LHS=r^2#

#:.r^2=-3rcostheta#

divide through by #r#

#r=-3costheta#