# How do you write the equation #y+2=7/8(x-3)# in standard form?

##### 2 Answers

That equation in standard form is

#### Explanation:

First, you can distribute the

After that subtract both sides by two:

#### Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

where A is a positive integer and B, C are integers.

#"rearrange " y+2=7/8(x-3)" into this form"#

#rArry+2=7/8x-21/8larrcolor(red)" distributing"#

#"subtract " 7/8x" from both sides"#

#y+2-7/8x=cancel(7/8x)cancel(-7/8x)-21/8#

#rArry+2-7/8x=-21/8#

#"subtract 2 from both sides"#

#ycancel(+2)cancel(-2)-7/8x=-21/8-2#

#rArry-7/8x=-37/8#

#"multiply through by " -8#

#rArr7x-8y=37larrcolor(red)" in standard form"#