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How do you write the expression #7^(1/2)# in radical form?

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Nam D. Share
Mar 18, 2018

Answer:

#sqrt(7)#

Explanation:

Given: #7^(1/2)#

Know that, #root(c)(a^b)=a^(b/c)#

Here, we got #a=7,b=1,c=2#, and so we got:

#root(2)(7^1)#

#=sqrt(7)#

Hope this helps!

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