How do you write the expression #9(p+1)(p+1)# using exponents? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Meave60 Jan 6, 2017 #9(p+1)^2# Explanation: #9(p+1)(p+1)# #(p+1)(p+1)=(p+1)^2# Add back the #9#. #9(p+1)^2# Answer link Related questions How do you simplify #c^3v^9c^-1c^0#? How do you simplify #(- 1/5)^-2 + (-2)^-2#? How do you simplify #(4^6)^2 #? How do you simplify #3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 #? How do you simplify #4^3ยท4^5#? How do you simplify #(5^-2)^-3#? How do you simplify and write #(-5.3)^0# with positive exponents? How do you factor #12j^2k - 36j^6k^6 + 12j^2#? How do you simplify the expression #2^5/(2^3 times 2^8)#? When can I add exponents? See all questions in Exponents Impact of this question 1495 views around the world You can reuse this answer Creative Commons License