How do you write the expression #a^(6/5)# in radical form?

2 Answers
Mar 29, 2017

#a^(6/5)=color(green)(aroot(5)a)#

Explanation:

#a^(6/5)#
#color(white)("XXX")=a^(5/5) * a^(1/5)#

#color(white)("XXX")=a * root(5)a#

Mar 29, 2017

#color(red)(aroot5a#

Explanation:

#5^(6/5)=root5(a^6)#

#:.=root5(a*a*a*a*a*a)#

#color(blue)(Note:#

#color(blue)(root5(a)*root5(a)*root5(a)*root5(a)*root5(a)=a#

#color(blue)(root5(a*a*a*a*a)=a#

#color(blue)(root5(2)*root5(2)*root5(2)*root5(2)*root5(2)=2#

#:.=color(red)(aroot5(a)#