How do you write the expression sin140^circcos50^circ+cos140^circsin50^circ as the sine, cosine, or tangent of an angle?

2 Answers
Aug 5, 2017

The answer is =sin(190^@)

Explanation:

We need

sin(a+b)=sina cosb+sinbcosa

Here,

a=140^@

and

b=50^@

Therefore,

sin140^@cos50^@+cos140^@sin50^@=sin(140^@+50^@)=sin190^@

Aug 5, 2017

sin190^@

Explanation:

"using the "color(blue)"addition formula for sine"

•color(white)(x)sin(A+-B)=sinAcosB+-cosAsinB

"here "A=140" and "B=50

rArrsin(140+50)^@=sin190^@