How do you write the first five terms of the sequence #a_n=1/(n^(3/2))#?

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Answer 1 · 2017-03-27T14:54:14

First five terms are #{1,1/(2sqrt2),1/(3sqrt3),1/8,1/(5sqrt5)}#

As #a_n=1/n^(3/2)#

#a_1=1/1^(3/2)=1#

#a_2=1/2^(3/2)=1/sqrt8=1/(2sqrt2)#

#a_3=1/3^(3/2)=1/sqrt27=1/(3sqrt3)#

#a_4=1/4^(3/2)=1/sqrt64=1/8#

#a_5=1/5^(3/2)=1/sqrt125=1/(5sqrt5)#

Hence, first five terms are #{1,1/(2sqrt2),1/(3sqrt3),1/8,1/(5sqrt5)}#