How do you write the first five terms of the sequence #a_n=(n+2)/n#?

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Answer 1 · 2017-02-14T07:11:34

First five terms are #{3,2,5/3,3/2,7/5}#

To find the first five terms of the sequence #a_n=(n+2)/n#, we need to put value of #n# from #1# to #5#.

Thus #a_1=(1+2)/1=3/1=3#

#a_2=(2+2)/2=4/2=2#

#a_3=(3+2)/3=5/3#

#a_4=(4+2)/4=6/4=3/2#

#a_5=(5+2)/5=7/5#

Hence, the first five terms are #{3,2,5/3,3/2,7/5}#