# How do you write the first six terms of the sequence a_n=(-n)^3?

Sep 16, 2016

${a}_{1} = - 1$

${a}_{2} = - 8$

${a}_{3} = - 27$

${a}_{4} = - 64$

${a}_{5} = - 125$

${a}_{6} = - 216$

#### Explanation:

We have: ${a}_{n} = {\left(- n\right)}^{3}$

In order to write the first six terms of the sequence we simply substitute $n$ with the number of the term:

$\implies {a}_{1} = {\left(- 1\right)}^{3} = - 1$

$\implies {a}_{2} = {\left(- 2\right)}^{3} = - 8$

$\implies {a}_{3} = {\left(- 3\right)}^{3} = - 27$

$\implies {a}_{4} = {\left(- 4\right)}^{3} = - 64$

$\implies {a}_{5} = {\left(- 5\right)}^{3} = - 125$

$\implies {a}_{6} = {\left(- 6\right)}^{3} = - 216$