How do you write the following quotient in standard form #(8+20i)/(2i)#?

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Answer 1 · 2016-09-04T16:31:52

#(8+20i)/(2i)=10-4i#

We should remember that #i^2=-1# and hence we can simplify the given quotient by multiplying numerator and denominator by #i#. As such

#(8+20i)/(2i)#

= #(i×(8+20i))/(i×2i)#

= #(8i+20i^2)/(2i^2)#

= #(8i+20×(-1))/(2×(-1))#

= #(-20+8i)/(-2)#

= #10-4i#