How do you write the formula of vanadium (IV) carbonate?

1 Answer
Apr 5, 2016

Since it is specified as vanadium(IV), we know that we are using the #+4# cation, #\mathbf("V"^(4+))#, as the roman numerals correspond to the cationic charge.

Also, carbonate is the #\mathbf("CO"_3^(2-))# polyatomic ion.

Therefore, we are looking at #"V"^(4+)# and #"CO"_3^(2-)# in constructing this molecular formula, and we would get:

#color(blue)("V"("CO"_3)_2)#