How do you write the function in standard form $y = - 6 {(x - 2)}^{2} - 9$ $y=-6(x-2)^2-9$ ?

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How do you write the function in standard form $y = - 6 {(x - 2)}^{2} - 9$ $y=-6(x-2)^2-9$ ?

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Answer 1 · 2018-04-29T04:37:43

$y = - 6 x^{2} + 24 x - 33$ $y = -6x^2 + 24x - 33$

Explanation:

$y = - 6 {(x - 2)}^{2} - 9$ $y = -6(x-2)^2 - 9$

To write an equation in standard form, it has be in the form $y = a x^{2} + b x + c$ $y = ax^2 + bx + c$ . To get this, let's distribute and simplify.

$y = - 6 (x - 2) (x - 2) - 9$ $y = -6(x-2)(x-2) - 9$

Expand $(x - 2) (x - 2)$ $(x-2)(x-2)$
$y = - 6 (x^{2} - 2 x - 2 x + 4) - 9$ $y = -6(x^2 - 2x - 2x + 4) - 9$

Combine like terms:
$y = - 6 (x^{2} - 4 x + 4) - 9$ $y = -6(x^2 - 4x + 4) - 9$

Multiply out the $- 6$ $-6$ :
$y = - 6 x^{2} + 24 x - 24 - 9$ $y = -6x^2 + 24x - 24 - 9$

Combine like terms:
$y = - 6 x^{2} + 24 x - 33$ $y = -6x^2 + 24x - 33$

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How do you write the function in standard form $y = - 6 {(x - 2)}^{2} - 9$ $y=-6(x-2)^2-9$ ?

1 Answer

Explanation:

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How do you write the function in standard form y=-6(x-2)^2-9y=−6(x−2)2−9y=-6(x-2)^2-9?

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How do you write the function in standard form $y = - 6 {(x - 2)}^{2} - 9$ $y=-6(x-2)^2-9$ ?