How do you write the function in standard form #y=-6(x-2)^2-9#?

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Answer 1 · 2018-04-29T04:37:43

#y = -6x^2 + 24x - 33#

#y = -6(x-2)^2 - 9#

To write an equation in standard form, it has be in the form #y = ax^2 + bx + c#. To get this, let's distribute and simplify.

#y = -6(x-2)(x-2) - 9#

Expand #(x-2)(x-2)#
#y = -6(x^2 - 2x - 2x + 4) - 9#

Combine like terms:
#y = -6(x^2 - 4x + 4) - 9#

Multiply out the #-6#:
#y = -6x^2 + 24x - 24 - 9#

Combine like terms:
#y = -6x^2 + 24x - 33#

Hope this helps!