# How do you write the inequality and solve given "three times a number increased by 8 is no more than the number decreased by 4"?

Oct 6, 2017

$a \le - 6$

#### Explanation:

Let the number be $a$,

Given that:
Three times a number increased by $8 \implies 3 a + 8$

'is no more than' means it can be the same as or less than the number decreased by $4$ :

$3 a + 8 \le a - 4$

Solving :
Take the terms with variable $a$ to left hand side and keep the other terms on right hand side. Apply transposition rules:

$3 a - a \le - 8 - 4$

$2 a \le - 12$

$a \le - 6$