How do you write the point slope form of the equation given (2,0) parallel to #y=1/3x+3#?

1 Answer
Jun 9, 2018

Answer:

#y-0=1/3(x-2)#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+c#

#"where m is the slope and b the y-intercept"#

#y=1/3x+3" is in this form"#

#"with slope "=1/3#

#• " Parallel lines have equal slopes"#

#"the equation of a line in "color(blue)"point-slope form"# is.

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=1/3" and "(x_1,y_1)=(2,0)#

#y-0=1/3(x-2)larrcolor(red)"in point-slope form"#

#"or "y=1/3(x-2)#