# How do you write the point slope form of the equation given (4,-5) and (0,-1)?

The equation of the line is $y = - x - 1$
The slope = $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} = \frac{- 1 - \left(- 5\right)}{0 - 4} = - \frac{4}{4} = - 1$
Let the equation of the line is $y = m x + c \mathmr{and} y = - 1 \cdot x + c$ The point $\left(4 , - 5\right)$ is on the line , so it will satisfy the equation. $y = - x = c \mathmr{and} - 5 = - 4 + c \therefore c = - 5 + 4 = - 1$ Hence the equation of the line is $y = - x - 1$ graph{-x-1 [-10, 10, -5, 5]} [Ans]