# How do you write the point slope form of the equation given (-8,2) and m=-3/4?

Aug 18, 2016

$y - 2 = - \frac{3}{4} \left(x + 8\right)$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{point-slope form}}$ is

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right) \text{ a point on the line}$

here $m = - \frac{3}{4} \text{ and } \left({x}_{1} , {y}_{1}\right) = \left(- 8 , 2\right)$

substitute these values into the equation.

$y - 2 = - \frac{3}{4} \left(x + 8\right) \text{ equation in point-slope form}$

It is usual.however, to distribute and collect like terms.

$\Rightarrow y - 2 = - \frac{3}{4} x - 6$

$\Rightarrow y = - \frac{3}{4} x - 4 \text{ in slope-intercept form}$