How do you write the prime factorization of $28x^2y$ ?

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Answer 1 · 2017-01-14T03:35:30

$2xx2xx7xx x xx x xx y$
[With the assumption that $x$ and $y$ are prime.]

The prime factors of 28 are: $2xx2xx7$

Since $x$ are $y$ are unknowns, I will express the factors of $x^2y$ as: $x xx x xx y$ [With the assumption that $x$ and $y$ are prime.]

Hence the prime factorisation of $28x^2y$ is: $2xx2xx7xx x xx x xx y$

How do you write the prime factorization of 28x^2y28x^2y?