# How do you write the standard equation for the circle passes through the origin, radius=10 and abcissa of the center is -6?

##### 1 Answer

Feb 24, 2016

#### Answer:

or

#### Explanation:

The "abcissa" in this question is equivalent to the

There are two possible

If the radius is

and if the

Applying the general form fro a circle with center

gives two possibilities:

The graph for

graph{(x+6)^2+(y+8)^2=100 [-27.37, 23.96, -19.48, 6.17]}

The graph for

graph{(x+6)^2+(y-8)^2=100 [-31.95, 19.37, -5.64, 20.02]}