# How do you write the standard equation of the circle with center (2, 3) and a diameter of 12?

Hence the diameter is $d = 12$ the radius is $r = \frac{d}{2} = 6$ and the circle equation is
${\left(x - 2\right)}^{2} + {\left(y - 3\right)}^{2} = {6}^{2}$