Question

How do you write the standard equation of the circle with center (2, 3) and a diameter of 12?

Answer 1

Hence the diameter is `d=12` the radius is `r=d/2=6` and the circle equation is

`(x-2)^2+(y-3)^2=6^2`

The graph is

graph{(x-2)^2+(y-3)^2=6^2 [-20, 20, -10, 10]}