Question

How do you write the standard equation of the circle with center (-4, 3) and a radius of 5?

Answer 1

`x^2+y^2+8x-6y=0" " "`standard form
`(x+4)^2+(y-3)^2=25" " "`center-radius form

Explanation:

`(x--4)^2+(y-3)^2=5^2`
`x^2+8x+16+y^2-6y+9=25`
`x^2+y^2+8x-6y=0`
God bless you...I hope the explanation helps...