# How do you write the standard form of a line given slope of 43− and passes through the point (4, 5)?

Dec 4, 2017

$y = 43 x - 167$

#### Explanation:

I'm assuming you meant that the gradient was $43$:

The standard equation of a straight line with gradient $m$ and intercepting the y axis at $c$ is:

$y = m x + c$

Since the line passes through the point $\left(4 , 3\right)$, we can form the following equation and solve for $c$:

$5 = 43 \left(4\right) + c$
$c = - 167$

Hence,
$y = 43 x - 167$