Question

How do you write the standard form of the equation of the circle with center (2, 3) and radius 4?

Answer 1

`(x-2)^2+(y-3)^2=16`

Explanation:

Use the standard equation of a circle:
`(x-h)^2+(y-k)^2=r^2`
h= x coordinate of the center
k= y coordinate of the center
r= radius

Plug in values:
`(x-2)^2+(y-3)^2=(4)^2`
`(x-2)^2+(y-3)^2=16`