How do you write the standard form of the equation of the circle with center (2, 3) and radius 4?

Mar 9, 2018

${\left(x - 2\right)}^{2} + {\left(y - 3\right)}^{2} = 16$

Explanation:

Use the standard equation of a circle:
${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$
h= x coordinate of the center
k= y coordinate of the center
${\left(x - 2\right)}^{2} + {\left(y - 3\right)}^{2} = {\left(4\right)}^{2}$
${\left(x - 2\right)}^{2} + {\left(y - 3\right)}^{2} = 16$