How do you write the standard form of the equation of the circle with the given the center (0,0), r=12?

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Answer 1 · 2016-04-19T02:08:12

#x^2 + y^2 = 12^2#

For a circle centered at #(a,b)# with radius #r#, the equation of the circle is given by

#(x-a)^2 + (y-b)^2 = r^2#

This follows from the Pythagoras Theorem. Refer to the diagram below.

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In this case, #(a,b) = (0,0)# and #r = 12#. Therefore, the equation of the circle is

#(x-0)^2 + (y-0)^2 = 12^2#

or after simplifying,

#x^2 + y^2 = 144#