# How do you write the standard form of the equation of the circle with the given the center (0,0), r=12?

##### 1 Answer

Apr 19, 2016

#### Explanation:

For a circle centered at

#(x-a)^2 + (y-b)^2 = r^2#

This follows from the Pythagoras Theorem. Refer to the diagram below.

In this case,

#(x-0)^2 + (y-0)^2 = 12^2#

or after simplifying,

#x^2 + y^2 = 144#