# How do you write the standard from of the equation of the circle given Center at (3, -6); radius = 5?

Nov 12, 2016

${\left(x - 3\right)}^{2} + {\left(y + 6\right)}^{2} = 25$

#### Explanation:

Standard Equation of a circle

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

where:

$C e n t e r : \left(h , k\right)$
$r a \mathrm{di} u s : r$

${\left(x - 3\right)}^{2} + {\left(y + 6\right)}^{2} = {5}^{2}$

$\implies {\left(x - 3\right)}^{2} + {\left(y + 6\right)}^{2} = 25$