# How do you write the standard from of the equation of the circle given Center is (-2,-3) and radius is: 3?

Jun 13, 2017

The standard Cartesian form for the equation of a circle is:

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2} \text{ [1]}$

Where $\left(h , k\right)$is the center and r is the radius

#### Explanation:

Substitute - 2 for h, -3 for k, and 3 for r in equation [1]:

${\left(x - \left(- 2\right)\right)}^{2} + {\left(y - \left(- 3\right)\right)}^{2} = {3}^{2} \text{ [2]}$

Here is a graph of the equation:

graph{(x - (-2))^2+ (y-(-3))^2 = 3^2 [-15, 5, -9, 1]}