# How do you write the standard from of the equation of the circle given center is (-2,5) and whose diameter is 12?

May 22, 2016

${\left(x + 2\right)}^{2} + {\left(y - 5\right)}^{2} = 36$

#### Explanation:

The standard form of the equation of a circle is.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where (a ,b) is the centre and r, the radius.

Here the centre = (-2 ,5) and radius = 6

$\Rightarrow \text{ equation is } {\left(x + 2\right)}^{2} + {\left(y - 5\right)}^{2} = 36$