How do you write this equation 4/3x^2+4/3y^2=1? in standard form and find the center and radius?

$\frac{4}{3} {x}^{2} + \frac{4}{3} {y}^{2} = 1 \implies 4 \cdot \left({x}^{2} + {y}^{2}\right) = 3 \implies {x}^{2} + {y}^{2} = {\left(\frac{\sqrt{3}}{2}\right)}^{2}$
Hence it is a circle with center at $\left(0 , 0\right)$ and radius $r = \frac{\sqrt{3}}{2}$