How do you write #x^3 y^-5# with a postive exponent?

2 Answers
Sep 7, 2015

Answer:

#x^3/y^5#

Explanation:

Recall that:

#1/a^n = a^-n#

This means that #y^-5 = 1/y^5#.

Thus:
#x^3y^-5#
#=x^3*1/y^5#
#=x^3/y^5#

Answer:

Here we only have to apply 1 law of indices or exponents formula
i.e:
#x^-n=1/x^n#

Explanation:

So now here we have #x^3##y^-5#,which can also be written as:
#x^3/y^5# (answer)
(note- #y^-5# is in the form of #x^-n# , so can be written in the form of #1/x^n# i.e, #1/y^5#).
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I hope this helps :)