How do you write #y = 1/2x-1# in standard form?

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Answer 1 · 2015-04-29T10:49:45

The equation given to us is in the Slope Intercept Form #y = m*x + c# where #m# is the slope and #c# is the Y intercept

The standard form of a linear equation is #ax + by = c#

So we first multiply both sides of this equation with 2

#2*y = 2((1/2)x - 1)#

#2y = x - 2#

Transposing #-2# to the left hand side, and #2y# to the right, we get

# 2 = x - 2y#

#color(green)(x - 2y = 2# is the Standard form of #y = 1/2x-1#