How do you write #y=12x# in standard form and what is A, B, C?

1 Answer
Apr 13, 2017

See the entire solution process below:

Explanation:

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

First, subtract #color(red)(12x)# from each side of the equation to place both the #x# and #y# term on the left side of the equation as required by the standard form:

#-color(red)(12x) + y = -color(red)(12x) + 12x#

#-12x + y = 0#

Because the #x# coefficient must be positive we will multiply each side of the equation by #color(red)(-1)#:

#color(red)(-1)(-12x + y) = color(red)(-1) xx 0#

#(color(red)(-1) xx -12x) + (color(red)(-1) xx y) = 0#

#color(red)(12)x - color(blue)(1)y = color(green)(0)#

#color(red)(A = 12)#

#color(blue)(B = -1)#

#color(green)(C = 0)#