How do you write #y+2= -3/4(x+1)# in standard form?

1 Answer
Apr 22, 2018

#3x+4y=-11#

Explanation:

Given:

#y+2=-3/4(x+1)#

The standard form for a linear equation is:

#Ax+By=C#

To convert #y+2=-3/4(x+1)# into standard form, first distribute the slope #-(3x)/4#.

#y+2=-(3x)/4-3/4#

Subtract #2# from both sides.

#y=-(3x)/4-3/4-2#

Multiply both sides by #4#.

#color(red)4xxy=color(black)cancel(color(red)(4))^1xx-(3x)/color(red)cancel(color(black)(4))^1-color(black)cancel(color(red)(4))^1xx3/color(red)cancel(color(black)(4))^1-4xx2#

Simplify.

#4y=-3x-3-8#

#4y=-3x-11#

Add #3x# to both sides.

#3x+4y=-11#