How do you write y+2= -3/4(x+1) in standard form?

Apr 22, 2018

$3 x + 4 y = - 11$

Explanation:

Given:

$y + 2 = - \frac{3}{4} \left(x + 1\right)$

The standard form for a linear equation is:

$A x + B y = C$

To convert $y + 2 = - \frac{3}{4} \left(x + 1\right)$ into standard form, first distribute the slope $- \frac{3 x}{4}$.

$y + 2 = - \frac{3 x}{4} - \frac{3}{4}$

Subtract $2$ from both sides.

$y = - \frac{3 x}{4} - \frac{3}{4} - 2$

Multiply both sides by $4$.

$\textcolor{red}{4} \times y = {\textcolor{b l a c k}{\cancel{\textcolor{red}{4}}}}^{1} \times - \frac{3 x}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} ^ 1 - {\textcolor{b l a c k}{\cancel{\textcolor{red}{4}}}}^{1} \times \frac{3}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} ^ 1 - 4 \times 2$

Simplify.

$4 y = - 3 x - 3 - 8$

$4 y = - 3 x - 11$

Add $3 x$ to both sides.

$3 x + 4 y = - 11$