# How do you write #y-3=2.5(x+1)# in standard form?

##### 1 Answer

Jan 22, 2017

#### Explanation:

The equation of a line in

#color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))# Rearrange

#y-3=2.5(x+1)" into this form"# distribute the bracket.

#rArry-3=2.5x+2.5# subtract y from both sides.

#cancel(y)cancel(-y)-3=2.5x-y+2.5#

#rArr0-3=2.5x-y+2.5# add 3 to both sides.

#0cancel(-3)cancel(+3)=2.5x-y+2.5+3#

#rArr2.5x-y+5.5=0larrcolor(red)" in standard form"#