# How do you write y-3=2.5(x+1) in standard form?

Jan 22, 2017

$2.5 x - y + 5.5 = 0$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{standard form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{a x + b y + c = 0} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

Rearrange $y - 3 = 2.5 \left(x + 1\right) \text{ into this form}$

distribute the bracket.

$\Rightarrow y - 3 = 2.5 x + 2.5$

subtract y from both sides.

$\cancel{y} \cancel{- y} - 3 = 2.5 x - y + 2.5$

$\Rightarrow 0 - 3 = 2.5 x - y + 2.5$

$0 \cancel{- 3} \cancel{+ 3} = 2.5 x - y + 2.5 + 3$
$\Rightarrow 2.5 x - y + 5.5 = 0 \leftarrow \textcolor{red}{\text{ in standard form}}$