# How do you write y = -3/2x + 3 in standard form?

Jun 14, 2017

$3 x + 2 y = 6$

#### Explanation:

Standard Form looks like :
$a x + b y = c$
where $a , b$ and $c$ are constants.

So we need to rearrange the formula to get both $x$ and $y$ to one side, and a number on the other side.

So from:

$y = - \frac{3}{2} x + 3$

We should get rid of the fraction first. To do this, multiply everything by 2:

$2 y = 2 \left(- \frac{3}{2} x\right) + 2 \left(3\right)$

$\implies 2 y = \frac{2 \cdot - 3}{2} x + 6$

$\implies 2 y = \frac{\cancel{2} \cdot - 3}{\cancel{2}} x + 6$

$\implies 2 y = - 3 x + 6$

Then we bring -3x to the other side by adding 3x to both sides:

$\implies 3 x + 2 y = - 3 x + 6 + 3 x$

$\implies 3 x + 2 y = \cancel{- 3 x} + 6 + \cancel{3 x}$

$\implies 3 x + 2 y = 6$

And you've got it in standard from now